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Chapter 5 · Class 12 Biology

Principles of Inheritance and Variation

1 exercises9 questions solved
Exercise 5.1Mendel's Laws, Chromosomal Theory and Variation
Q1

Mention the advantages of selecting pea plant for experiment by Mendel.

Solution

Mendel chose the garden pea (Pisum sativum) because of several advantages: 1. Availability of contrasting characters: • Pea has 7 pairs of contrasting traits (tall/dwarf, round/wrinkled seed, etc.) that are easily observable and distinguishable 2. Bisexual flowers: • Pea flowers are bisexual (have both stamens and pistil) and are naturally self-fertilising • Allowed easy controlled cross-pollination by hand 3. Cleistogamous flowers: • Flowers naturally self-pollinate before opening → ensures pure lines • Easy to maintain pure breeding lines 4. Easy artificial cross-pollination: • Large flowers are easy to manipulate — emasculation (removal of stamens) and cross-pollination done easily 5. Short life cycle: • Annual plant with short generation time → results available in one season 6. Large number of offspring: • Produces many seeds per cross → statistically reliable ratios 7. Inexpensive and easy to grow: • Readily available, cheap, easy to cultivate in garden 8. Distinct and stable traits: • The 7 characters Mendel chose show clear-cut differences without intermediates • Traits remained stable across generations 9. Both true-breeding varieties and hybrids available: • True-breeding lines for each trait already existed for use in experiments
Q2

Differentiate between the following: (a) Dominance and Recessiveness (b) Homozygous and Heterozygous (c) Monohybrid and Dihybrid.

Solution

(a) Dominance vs Recessiveness: Dominance: • The allele that expresses its effect and masks the effect of the other allele • Expressed in both homozygous (AA) and heterozygous (Aa) conditions • Represented by capital letter (e.g., T for tallness) • Example: T (tall) is dominant over t (dwarf) Recessiveness: • The allele whose effect is masked in the presence of a dominant allele • Expressed only in homozygous condition (tt) • Represented by lowercase letter • Example: t (dwarf) is recessive; expressed only in tt (b) Homozygous vs Heterozygous: Homozygous: • Both alleles for a trait are identical (same) • E.g., TT (homozygous dominant) or tt (homozygous recessive) • Breeds true — produces only one type of gamete • Also called pure-breeding Heterozygous: • The two alleles for a trait are different • E.g., Tt (heterozygous) • Does not breed true — produces two types of gametes (T and t) • Also called hybrid (c) Monohybrid vs Dihybrid: Monohybrid: • Cross involving one pair of contrasting characters (one gene locus) • Example: Tt × Tt (tall × tall) • F2 phenotypic ratio: 3:1 • F2 genotypic ratio: 1:2:1 Dihybrid: • Cross involving two pairs of contrasting characters (two gene loci) • Example: TtRr × TtRr • F2 phenotypic ratio: 9:3:3:1 (when genes on separate chromosomes) • Demonstrates the Law of Independent Assortment
Q3

A diploid organism is heterozygous for 4 loci, how many types of gametes can it produce?

Solution

Formula: Number of gamete types = 2ⁿ, where n = number of heterozygous loci Given: heterozygous for 4 loci (all 4 genes are heterozygous) Number of gamete types = 2⁴ = 16 different types of gametes Explanation: • For each heterozygous locus (Aa), the organism produces 2 types of gametes: A or a • For 4 independent heterozygous loci: 2 × 2 × 2 × 2 = 16 combinations Example: AaBbCcDd organism produces gametes: ABCD, ABCd, ABcD, ABcd, AbCD, AbCd, AbcD, Abcd, aBCD, aBCd, aBcD, aBcd, abCD, abCd, abcD, abcd = 16 types This assumes the 4 loci are on separate chromosomes (independent assortment).
Q4

Explain the Law of Dominance using a monohybrid cross.

Solution

Law of Dominance states: When two alternative forms of a character (alleles) are present together in a hybrid, only one (dominant) is expressed; the other (recessive) is suppressed in the F1 generation. Monohybrid Cross Experiment: Parents (P): TT (tall) × tt (dwarf) • Pure tall plant (TT) × pure dwarf plant (tt) F1 generation: All plants are Tt (tall) • The T allele is dominant — it is expressed • The t allele is recessive — it is suppressed (hidden) • All F1 hybrids are tall → Law of Dominance demonstrated F2 generation (F1 × F1: Tt × Tt): • Gametes from each parent: T or t Punnett square: T t T | TT | Tt | t | Tt | tt | F2 genotypes: 1 TT : 2 Tt : 1 tt F2 phenotypes: 3 Tall : 1 Dwarf (3:1 ratio) Observations proving the Law: 1. F1 plants are ALL tall → dominant trait (T) completely masks recessive trait (t) 2. Recessive trait (dwarf) reappears in F2 → it was not lost, only suppressed 3. In F2: 3 tall : 1 dwarf — confirming dominant (T) is expressed in TT and Tt, recessive (t) only in tt Conclusion: Tallness (T) is dominant over dwarfness (t). In a heterozygote (Tt), only the dominant allele determines the phenotype.
Q5

Define and design a test cross.

Solution

Test Cross: A cross between an organism with dominant phenotype but unknown genotype (could be homozygous dominant AA or heterozygous Aa) and a homozygous recessive organism (aa). Purpose: To determine whether the dominant phenotype organism is homozygous (AA) or heterozygous (Aa). Design: Case 1 — If unknown organism is homozygous dominant (AA): AA × aa → All offspring: Aa (all dominant phenotype) Ratio: 100% dominant : 0% recessive → All offspring show dominant phenotype → Parent is AA Case 2 — If unknown organism is heterozygous (Aa): Aa × aa → Offspring: Aa (dominant) and aa (recessive) Ratio: 1 dominant : 1 recessive (1:1) → Half offspring show recessive phenotype → Parent is Aa Example: Tall pea plant (T?) × dwarf pea plant (tt): • If all offspring tall → parent is TT • If offspring are 1 tall : 1 dwarf → parent is Tt The homozygous recessive parent (aa/tt) is called the test parent because: • It contributes only recessive alleles • So the phenotype of offspring directly reveals the gametes (and genotype) of the unknown parent Conclusion: A 1:1 ratio in the offspring indicates heterozygosity; a 1:0 ratio indicates homozygosity.
Q6

Using a Punnett square, work out the distribution of phenotypic features in the first filial generation after a cross between a homozygous female and a heterozygous male for a single locus.

Solution

Cross: Homozygous female × Heterozygous male Let dominant allele = A, recessive allele = a Homozygous female can be either: Case 1: Homozygous dominant female (AA) × Heterozygous male (Aa) Female gametes: all A Male gametes: A or a Punnett square: A (female) A (female) A (♂) | AA | AA | a (♂) | Aa | Aa | F1 genotypes: 1 AA : 1 Aa (= 2 AA : 2 Aa) F1 phenotypes: ALL show dominant phenotype (100%) Ratio: All dominant : 0 recessive Case 2: Homozygous recessive female (aa) × Heterozygous male (Aa) Female gametes: all a Male gametes: A or a Punnett square: a (female) a (female) A (♂) | Aa | Aa | a (♂) | aa | aa | F1 genotypes: 1 Aa : 1 aa F1 phenotypes: 1 dominant (Aa) : 1 recessive (aa) Ratio: 1:1 Conclusion: When a homozygous dominant female is crossed with a heterozygous male, all F1 offspring show the dominant phenotype. When a homozygous recessive female is crossed with a heterozygous male, offspring show 1:1 ratio (like a test cross).
Q7

When are autosomes and sex chromosomes similar to each other?

Solution

Autosomes and sex chromosomes are similar to each other in the following conditions: 1. In females (XX condition): • Females carry two X chromosomes (XX) • The two X chromosomes behave like autosomes in terms of being a matched (homologous) pair • Like autosomes, both X chromosomes can pair, cross over, and segregate normally during meiosis 2. In homogametic sex (ZZ condition in birds): • In birds, males are ZZ (homogametic) — both sex chromosomes are identical • ZZ males are similar to autosomes in that they have a matched pair 3. In organisms where sex chromosomes are not differentiated: • In some organisms, the sex chromosomes look morphologically identical to autosomes • Example: early stages of sex chromosome evolution 4. Structural similarity: • The sex chromosomes (particularly both X chromosomes in females) contain the pseudoautosomal regions (PARs) that behave like autosomes — recombination occurs here during meiosis • These PAR regions on X and Y (or X and X) are functionally like autosomes In males (XY): X and Y chromosomes are NOT similar — they differ in size and gene content. Y is smaller and has fewer genes. They can only pair at pseudoautosomal regions. Conclusion: Autosomes and sex chromosomes are most similar in females (XX) where the two sex chromosomes are homologous pairs, similar to autosomes.
Q8

Explain with suitable examples: (a) Codominance (b) Incomplete dominance.

Solution

(a) Codominance: • Both alleles are equally expressed in the heterozygote — neither is dominant or recessive • Both alleles contribute equally to the phenotype • The F1 hybrid shows BOTH parental traits simultaneously Example: ABO Blood Group system (multiple alleles: Iᴬ, Iᴮ, i) • Iᴬ and Iᴮ are codominant alleles • Person with genotype IᴬIᴮ has blood group AB • Both A antigens (from Iᴬ) and B antigens (from Iᴮ) are expressed on red blood cells • Neither allele masks the other — both are fully expressed Another example: Roan coat in cattle • Red (Cᴿ) × White (Cᵂ) → Roan (CᴿCᵂ): both red and white hairs present (b) Incomplete Dominance: • Neither allele is completely dominant — heterozygote shows an intermediate phenotype • The F1 hybrid shows a blending of the two parental traits • Also called partial dominance or blending inheritance (though not true blending) Example: Snapdragon (Antirrhinum) / Four O'Clock plant (Mirabilis jalapa): Cross: Red (RR) × White (rr) F1: Rr → Pink flowers (intermediate) F2: RR (Red) : Rr (Pink) : rr (White) = 1:2:1 Note: In incomplete dominance, phenotypic and genotypic ratios in F2 are BOTH 1:2:1 (Unlike Mendelian dominance where phenotypic ratio is 3:1 and genotypic is 1:2:1) Difference: • Codominance: both phenotypes expressed simultaneously (e.g., AB blood) • Incomplete dominance: intermediate (blended) phenotype (e.g., pink from red × white)
Q9

What are multiple alleles? Explain ABO blood group with the help of a suitable example.

Solution

Multiple Alleles: • When a gene has more than two allelic forms (more than two variants) in a population, it is called multiple alleles • A single individual carries only two alleles (one on each homologous chromosome), but in the population, more than two variants exist • Example: ABO blood group gene has three alleles: Iᴬ, Iᴮ, and i ABO Blood Group System: Controlled by a single gene (I gene) with 3 alleles: Iᴬ, Iᴮ, and i Allele properties: • Iᴬ: codes for enzyme that adds A antigen to RBC surface • Iᴮ: codes for enzyme that adds B antigen to RBC surface • i: codes for non-functional enzyme (no antigen added) • Iᴬ and Iᴮ are both dominant over i, but codominant to each other Blood groups and genotypes: | Blood Group | Antigens on RBC | Antibodies in Plasma | Genotypes | |---|---|---|---| | A | A | Anti-B | IᴬIᴬ or Iᴬi | | B | B | Anti-A | IᴮIᴮ or Iᴮi | | AB | A and B | None | IᴬIᴮ | | O | None | Anti-A and Anti-B | ii | Example of a cross: Parents: Blood group A (IᴬIᴮ) × Blood group O (ii) Wait — IᴬIᴮ is blood group AB. Correct example: Parents: Blood group A (Iᴬi) × Blood group B (Iᴮi) Offspring: IᴬIᴮ (AB), Iᴬi (A), Iᴮi (B), ii (O) — all four blood groups possible! Importance: Critical for blood transfusion compatibility.
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