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Carbon and its Compounds: Class 10 Science Practice Questions

30 original exam-pattern questions with full answers, matched to the current CBSE Class 10 paper design, including case-based questions. Attempt each question before opening the answer — or start a free 14-day trial ↓ for the full bank.

Q1Case-based4 marks

Meera works in a food quality testing laboratory. One day, she receives four different liquid samples labelled P, Q, R and S for identification. She is told that each sample is one of the following: ethanol, ethanoic acid, a soap solution, or a detergent solution. She performs a litmus test, a sodium bicarbonate test, and a hard water test on each sample, and records her observations in a table.

Read the following passage carefully and answer the questions that follow:

Meera works in a food quality testing laboratory. One day, she receives four different liquid samples labelled P, Q, R and S for identification. She is told that each sample is one of the following: ethanol, ethanoic acid, a soap solution, or a detergent solution. To identify them, she performs the following tests:

• Test 1 (Litmus test): She dips blue and red litmus paper into each sample.
• Test 2 (Sodium bicarbonate test): She adds a small amount of NaHCO₃ to each sample.
• Test 3 (Hard water test): She adds each sample to hard water (containing Ca²⁺ and Mg²⁺ ions) and shakes the mixture.

Her observations are summarised below:

| Sample | Litmus test | NaHCO₃ test | Hard water test |
|--------|-------------|-------------|------------------|
| P | Turns blue litmus red | Brisk effervescence, colourless gas evolved | Lather forms |
| Q | No change | No change | Lather forms freely, no scum |
| R | No change | No change | Lather forms, but white curdy precipitate forms |
| S | No change | No change | No lather, no precipitate |

(a) Identify sample P and name the gas evolved in the NaHCO₃ test. [1 mark]
(b) Identify sample Q and explain why it forms lather freely even in hard water. [1 mark]
(c) Sample R forms a white curdy precipitate with hard water. Write the chemical equation for this reaction and state one advantage of sample Q over sample R in daily use. [2 marks]
OR
(c) Sample S is ethanol. Meera heats sample S gently with sample P in the presence of a few drops of concentrated H₂SO₄. Name the type of reaction that occurs, write the equation for this reaction, and state the role of concentrated H₂SO₄ in this reaction. [2 marks]

Show answer
(a) Sample P is ethanoic acid (acetic acid / CH₃COOH).
The gas evolved in the NaHCO₃ test is carbon dioxide (CO₂).
[Award ½ mark for correct identification of P; ½ mark for naming CO₂]

(b) Sample Q is the detergent solution.
Detergents contain sulphonate (–SO₃Na) or sulphate (–OSO₃Na) groups. The calcium and magnesium salts of sulphonates are soluble in water, so they do not react with the Ca²⁺ and Mg²⁺ ions present in hard water. Therefore, no scum is formed and lather is produced freely even in hard water.
[Award ½ mark for correct identification of Q; ½ mark for correct explanation]

(c) Sample R is a soap solution. The white curdy precipitate is formed when soap reacts with Ca²⁺ ions in hard water to produce an insoluble calcium salt of the fatty acid (scum).

Chemical equation:
2C₁₇H₃₅COONa + CaCl₂ → (C₁₇H₃₅COO)₂Ca↓ + 2NaCl
(sodium stearate) (calcium stearate — white scum)

One advantage of sample Q (detergent) over sample R (soap) in daily use:
Detergent works effectively in hard water without forming scum, whereas soap reacts with Ca²⁺/Mg²⁺ ions in hard water to form an insoluble scum, wasting the soap and reducing its cleaning action.
[Award 1 mark for the correct balanced equation with precipitate symbol ↓; 1 mark for a correct stated advantage]

OR

(c) The type of reaction that occurs when ethanol (sample S) is heated with ethanoic acid (sample P) in the presence of concentrated H₂SO₄ is esterification (also called a condensation reaction).

Equation:
CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O
(ethanoic acid) (ethanol) (ethyl ethanoate) (water)
[Conditions: conc. H₂SO₄, heat — written above/below the reversible arrow]

Role of concentrated H₂SO₄: Concentrated H₂SO₄ acts as both a catalyst (speeds up the reaction) and a dehydrating agent (removes the water produced, helping to drive the equilibrium towards the formation of the ester).
[Award 1 mark for naming the reaction AND writing the correct balanced equation with reversible arrow and conditions; 1 mark for stating BOTH roles of conc. H₂SO₄ — catalyst AND dehydrating agent]
Q2Case-based4 marks

Riya is a Class 10 student who is learning about carbon compounds in her chemistry class. Her teacher shows her four bottles labelled P, Q, R and S containing different organic liquids. She is told the following:

• Bottle P contains a 2-carbon compound with an –OH functional group.
• Bottle Q contains a 2-carbon compound with a –COOH functional group.
• Bottle R contains the product formed when P and Q react together in the presence of conc. H₂SO₄.
• Bottle S contains the product formed when R is treated with NaOH solution.

Riya is a Class 10 student who is learning about carbon compounds in her chemistry class. Her teacher shows her four bottles labelled P, Q, R and S containing different organic liquids. She is told the following:

• Bottle P contains a 2-carbon compound with an –OH functional group.
• Bottle Q contains a 2-carbon compound with a –COOH functional group.
• Bottle R contains the product formed when P and Q react together in the presence of conc. H₂SO₄.
• Bottle S contains the product formed when R is treated with NaOH solution.

Answer the following questions based on the above information:

(a) Identify the compounds in bottles P and Q. Write their IUPAC names and molecular formulae.

(b) Write the balanced chemical equation for the reaction between P and Q that produces R. Name the type of reaction and state the role of conc. H₂SO₄ in this reaction.

(c) Name the compound in bottle S and write the balanced chemical equation for its formation from R. What is this reaction called, and what is its industrial importance?

Show answer
(a) Bottle P contains Ethanol (common name: Alcohol / Grain alcohol). IUPAC name: Ethanol. Molecular formula: C₂H₅OH.

Bottle Q contains Ethanoic acid (common name: Acetic acid). IUPAC name: Ethanoic acid. Molecular formula: CH₃COOH.

[1 mark — ½ for each correct identification with name and formula]

(b) The reaction between ethanol (P) and ethanoic acid (Q) is:

CH₃COOH + C₂H₅OH ⇌ (conc. H₂SO₄, Heat) CH₃COOC₂H₅ + H₂O

(Ethanoic acid + Ethanol → Ethyl ethanoate + Water)

The compound in bottle R is Ethyl ethanoate (an ester).

Type of reaction: Esterification (a reversible reaction — note the ⇌ sign).

Role of conc. H₂SO₄: It acts as a catalyst (speeds up the reaction) and also as a dehydrating agent (removes water formed during the reaction, driving the equilibrium forward to produce more ester).

[1 mark — ½ for correct balanced equation with ⇌ and conditions; ½ for naming reaction type and role of H₂SO₄]

(c) Bottle S contains Sodium ethanoate (CH₃COONa) and ethanol (C₂H₅OH).

The balanced chemical equation for the reaction of ethyl ethanoate (R) with NaOH is:

CH₃COOC₂H₅ + NaOH → CH₃COONa + C₂H₅OH

(Ethyl ethanoate + Sodium hydroxide → Sodium ethanoate + Ethanol)

This reaction is called Saponification. It is the reverse of esterification — an ester reacts with a base (NaOH or KOH) to give the sodium/potassium salt of the carboxylic acid and alcohol.

Industrial importance: Saponification is the basis of soap manufacture. Vegetable oils or animal fats (which are esters of long-chain fatty acids) are treated with NaOH or KOH to produce soap (sodium or potassium salts of fatty acids) and glycerol.

[2 marks — 1 for correct name and balanced equation; 1 for naming saponification and its industrial importance in soap making]
Q3Case-based4 marks

Priya is working on a science project about everyday food items. She notices that her mother uses baking soda while making pancakes, and the pancakes rise and become fluffy. She also observes that vinegar (a dilute solution of ethanoic acid) is used as a preservative in pickles. Curious about the chemistry involved, she investigates reactions of ethanoic acid and ethanol with different substances.

Priya is working on a science project about everyday food items. She notices that her mother uses baking soda while making pancakes, and the pancakes rise and become fluffy. She also observes that vinegar (a dilute solution of ethanoic acid) is used as a preservative in pickles. Curious about the chemistry involved, Priya decides to investigate.

She takes two test tubes:
- Test tube A: A pinch of baking soda + 2 mL of vinegar
- Test tube B: A piece of sodium metal + 2 mL of ethanol

She observes brisk effervescence in both test tubes and collects the gas evolved in each case.

(a) Identify the gas evolved in Test tube A. Name the type of chemical reaction taking place in it.

(b) Identify the gas evolved in Test tube B. State ONE property that can be used to distinguish the gas in Test tube A from the gas in Test tube B.

(c) Priya then takes a fresh sample of ethanoic acid and adds a few drops of universal indicator to it. She observes the indicator turns orange-red. She also adds a few drops of universal indicator to ethanol and observes it turns green.

Explain why ethanoic acid turns the indicator orange-red while ethanol turns it green. Also write the IUPAC name and one common use of ethanoic acid.

Show answer
(a) Gas evolved in Test tube A: Carbon dioxide (CO₂) ↑

The reaction between baking soda (sodium hydrogen carbonate, NaHCO₃) and vinegar (ethanoic acid, CH₃COOH) produces carbon dioxide gas, which causes the brisk effervescence.

Balanced equation:
NaHCO₃ + CH₃COOH → CH₃COONa + H₂O + CO₂↑

Type of reaction: Double displacement reaction (acid–carbonate reaction). It is a double displacement reaction because two compounds exchange their ions to form new products.

[1 mark]

(b) Gas evolved in Test tube B: Hydrogen (H₂) ↑

Sodium is a highly reactive metal and reacts with ethanol to produce sodium ethoxide and hydrogen gas.

Balanced equation:
2Na + 2C₂H₅OH → 2C₂H₅ONa + H₂↑

Distinguishing property: CO₂ (from Test tube A) turns lime water milky, whereas H₂ (from Test tube B) burns with a 'pop' sound when a burning splint is brought near it. CO₂ does not burn and extinguishes a flame, while H₂ is combustible.

[1 mark]

(c) Ethanoic acid (CH₃COOH) is an organic acid. It dissociates in water to release H⁺ (hydrogen) ions:

CH₃COOH ⇌ CH₃COO⁻ + H⁺

Because it releases H⁺ ions, its solution is acidic (pH < 7). Universal indicator turns orange-red in acidic solutions, which is why Priya observes an orange-red colour.

Ethanol (C₂H₅OH) is a neutral organic compound. It does not release H⁺ or OH⁻ ions in water, so its solution has a pH close to 7 (neutral). Universal indicator turns green in neutral solutions, hence Priya observes a green colour.

Ethanoic acid is a weak acid — it only partially dissociates in water, giving fewer H⁺ ions compared to strong acids like HCl. This is why its pH is not as low as that of a strong acid, but it is still acidic enough to turn the indicator orange-red rather than deep red.

IUPAC name of ethanoic acid: Ethanoic acid (common name: Acetic acid; formula: CH₃COOH)

One common use: Ethanoic acid is used as a preservative in pickles and food products (vinegar is a 5–8% solution of ethanoic acid).

[2 marks]
Q4Case-based4 marks

A food chemist is studying the properties of four organic compounds found in common household items. She labels them P, Q, R, and S.

• Compound P is present in vinegar. It has a pungent, sour smell and turns blue litmus red. When sodium carbonate is added to it, brisk effervescence is observed.
• Compound Q is present in alcoholic beverages. It has a pleasant smell and is completely miscible with water. When compound Q is warmed with compound P in the presence of a few drops of concentrated sulphuric acid, a sweet-smelling compound T is formed.
• Compound R is obtained when compound T is boiled with sodium hydroxide solution. The products of this reaction are compound Q and the sodium salt of compound P.
• Compound S is obtained by the dehydration of compound Q using excess concentrated sulphuric acid at 443 K. It decolourises bromine water.

Read the following passage and answer the questions that follow.

A food chemist is studying the properties of four organic compounds found in common household items. She labels them P, Q, R, and S.

• Compound P is present in vinegar. It has a pungent, sour smell and turns blue litmus red. When a small piece of sodium carbonate is added to it, brisk effervescence is observed.
• Compound Q is present in alcoholic beverages. It has a pleasant smell and is completely miscible with water. When compound Q is warmed with compound P in the presence of a few drops of concentrated sulphuric acid, a sweet-smelling compound T is formed.
• Compound R is obtained when compound T is boiled with sodium hydroxide solution. The products of this reaction are compound Q and the sodium salt of compound P.
• Compound S is obtained by the dehydration of compound Q using excess concentrated sulphuric acid at 443 K. It decolourises bromine water.

(a) Identify compounds P and Q. Write their IUPAC names and molecular formulas.
(b) Name the type of reaction that occurs when compound Q reacts with compound P in the presence of concentrated sulphuric acid. Write the balanced chemical equation for this reaction.
(c) Identify compound S. State the structural feature of compound S that allows it to decolourise bromine water, and name the type of reaction involved. OR (c) The chemist notices that compound Q burns with a blue, non-sooty flame, while a higher homologue of Q containing four carbon atoms burns with a slightly sooty flame. Explain why the nature of the flame changes as the carbon chain length increases. Also state one use of compound Q as a fuel.

Show answer
MARKING SCHEME — 4 marks total

(a) Identification of P and Q [1 mark]

Compound P: Ethanoic acid (Acetic acid) — CH₃COOH

Clue: present in vinegar; pungent sour smell; turns blue litmus red; reacts with Na₂CO₃ to give CO₂ (brisk effervescence) — all characteristic of a carboxylic acid. Since vinegar contains the 2-carbon carboxylic acid:
IUPAC name: Ethanoic acid
Molecular formula: CH₃COOH (or C₂H₄O₂)

Compound Q: Ethanol — C₂H₅OH

Clue: present in alcoholic beverages; pleasant smell; miscible with water; reacts with ethanoic acid (P) to form a sweet-smelling compound (ester).
IUPAC name: Ethanol
Molecular formula: C₂H₅OH (or C₂H₆O)

[Award ½ mark for correct identification of each compound with IUPAC name and formula]

(b) Type of reaction and balanced equation [1 mark]

The reaction between compound Q (ethanol) and compound P (ethanoic acid) in the presence of concentrated sulphuric acid is called Esterification.

Concentrated H₂SO₄ acts as both a catalyst and a dehydrating agent.

The product T is Ethyl ethanoate (ethyl acetate) — a sweet-smelling ester.

Balanced chemical equation:

CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O
(conc. H₂SO₄, Heat above arrow)

[Award ½ mark for naming the reaction as esterification; ½ mark for correct balanced equation with reversible arrow and condition]

Note: The reversible arrow (⇌) is mandatory — esterification is a reversible reaction.

(c) MAIN OPTION — Compound S and bromine water decolourisation [2 marks]

Compound S is Ethene (Ethylene) — CH₂=CH₂

It is formed by the dehydration of ethanol (Q) using excess concentrated H₂SO₄ at 443 K:

C₂H₅OH →(conc. H₂SO₄, 443 K)→ CH₂=CH₂ + H₂O

Structural feature: Compound S (ethene) contains a carbon–carbon double bond (C=C). This makes it an unsaturated compound.

The C=C double bond allows ethene to undergo addition reactions. When ethene reacts with bromine water, bromine adds across the double bond:

CH₂=CH₂ + Br₂ → CH₂Br–CH₂Br
(ethene) (bromine water, orange-brown) → (1,2-dibromoethane, colourless)

The orange-brown colour of bromine water disappears because bromine is consumed in the addition reaction — this is why compound S decolourises bromine water.

Type of reaction: Addition reaction

[Award 1 mark for correct identification of S as ethene with the structural feature (C=C / unsaturated); 1 mark for naming the reaction as addition reaction and explaining decolourisation of bromine water]

OR

(c) ALTERNATE OPTION — Nature of flame and use of ethanol as fuel [2 marks]

Compound Q is ethanol (C₂H₅OH), and a higher homologue with four carbons is butan-1-ol (C₄H₉OH) or butane (C₄H₁₀) depending on context — here the reference is to a higher alkyl compound.

Why the flame becomes sooty as carbon chain increases:

Ethanol (Q) has a relatively low proportion of carbon compared to hydrogen and oxygen in its molecule. When it burns, there is sufficient oxygen available for complete combustion, producing CO₂ and H₂O with a blue, non-sooty flame.

As the length of the carbon chain increases (higher homologues), the percentage of carbon in the molecule increases. The available oxygen becomes insufficient to burn all the carbon completely. This leads to incomplete combustion — some carbon is released as fine carbon particles (soot), producing a yellow, sooty/luminous flame.

In general: Higher carbon content → higher tendency for incomplete combustion → sooty flame.

One use of compound Q (ethanol) as a fuel:
Ethanol is used as a biofuel — it is blended with petrol (e.g. 10–20% ethanol blend) to run motor vehicles, reducing dependence on fossil fuels and lowering carbon emissions.

[Award 1 mark for correct explanation of sooty flame with reference to incomplete combustion and increasing carbon content; 1 mark for one valid use of ethanol as a fuel]
Q5Case-based4 marks

A student named Priya is working in a chemistry lab. She takes 10 mL of coconut oil in a beaker and adds 30 mL of concentrated NaOH solution to it. She heats the mixture gently while stirring continuously for about 20 minutes. After heating, she adds a large quantity of common salt (NaCl) solution to the mixture and stirs it.

A student named Priya is working in a chemistry lab. She takes 10 mL of coconut oil in a beaker and adds 30 mL of concentrated NaOH solution to it. She heats the mixture gently while stirring continuously for about 20 minutes. After heating, she adds a large quantity of common salt (NaCl) solution to the mixture and stirs it.

Based on this activity, answer the following questions:

(a) Name the type of chemical reaction that takes place when NaOH reacts with coconut oil. Write the general equation for this reaction.

(b) Why does Priya add common salt (NaCl) solution at the end of the activity?

(c) A classmate observes that the soap formed does not lather well when tested with tap water collected from a nearby bore well, but lathers well with distilled water. Explain why this happens. Also suggest ONE advantage of using synthetic detergents over soap in such a situation.

Show answer
(a) The reaction that takes place is called Saponification. It is the reaction in which a fat or oil (ester of glycerol and fatty acids) is hydrolysed by a strong base (NaOH or KOH) to form soap (sodium or potassium salt of a long-chain fatty acid) and glycerol.

General equation:

Fat/Oil (Ester) + NaOH →(Heat)→ Soap (Sodium salt of fatty acid) + Glycerol

For example, using a representative fatty acid component:

C₁₇H₃₅COOC₃H₅ (fat) + 3NaOH →(Heat)→ 3C₁₇H₃₅COONa + C₃H₅(OH)₃
(Soap / Sodium stearate) (Glycerol)

[1 mark: name 'saponification' + general equation correctly stated]

(b) Common salt (NaCl) is added to the reaction mixture to precipitate (separate out) the soap from the solution. Soap is insoluble in a concentrated salt solution. The addition of NaCl increases the ionic strength of the solution, reducing the solubility of soap, causing it to separate out and float to the surface as a solid mass. This process is called salting out.

[1 mark: correct reason — soap is insoluble in concentrated NaCl / salting out]

(c) Bore well water is hard water. It contains dissolved calcium (Ca²⁺) and magnesium (Mg²⁺) salts. When soap is used in hard water, it reacts with these salts to form an insoluble white precipitate called scum (calcium or magnesium stearate). Since the soap is consumed in forming scum, little or no lather is produced. Distilled water is soft water — it contains no Ca²⁺ or Mg²⁺ ions — so soap dissolves freely and lathers well.

Advantage of synthetic detergents: Synthetic detergents contain sulphonate (–SO₃Na) or sulphate (–OSO₃Na) groups. The calcium and magnesium salts of these groups are soluble in water. Therefore, detergents do not form scum with hard water and produce lather even in bore well (hard) water.

[1 mark: correct explanation of why soap fails in hard water — Ca²⁺/Mg²⁺ ions form insoluble scum]
[1 mark: advantage of detergent — works in hard water because its calcium/magnesium salts are soluble / no scum formed]
Q6Case-based4 marks

A food scientist is developing a new cooking oil product. She notices that the oil, which contains long-chain unsaturated fatty acids, becomes solid at room temperature after a specific industrial process. She also observes that when a small piece of sodium metal is dropped into ethanol (one of the solvents used in her lab), a brisk effervescence occurs. Later, she tests the cleaning ability of two different products — a soap and a synthetic detergent — in the local hard water supply and records her observations.

A food scientist is developing a new cooking oil product. She notices that the oil, which contains long-chain unsaturated fatty acids, becomes solid at room temperature after a specific industrial process. She also observes that when a small piece of sodium metal is dropped into ethanol (one of the solvents used in her lab), a brisk effervescence occurs. Later, she tests the cleaning ability of two different products — a soap and a synthetic detergent — in the local hard water supply and records her observations.

Based on the above scenario, answer the following questions:

(a) Name the industrial process by which the unsaturated liquid oil is converted into a solid fat. Write the chemical equation for this process using a general unsaturated compound (alkene) as an example.

(b) Identify the gas evolved when sodium reacts with ethanol. Write the balanced chemical equation for this reaction.

(c) The food scientist finds that soap does not lather well in the local hard water, but the synthetic detergent lathers freely. Give TWO reasons to explain this difference in behaviour.

Show answer
(a) The process is called Hydrogenation (also called catalytic hydrogenation or hardening of oils).

In this process, hydrogen gas (H₂) is added across the C=C double bonds of unsaturated fatty acids in the presence of a nickel (Ni) catalyst at a suitable temperature. The unsaturated liquid oil is converted into a saturated solid fat.

Chemical equation using a general alkene as example:

CH₂=CH₂ + H₂ →(Ni, heat)→ CH₃–CH₃

(ethene) (ethane)

[Award ½ mark for correctly naming hydrogenation; ½ mark for stating Ni catalyst and heat as conditions; ½ mark for correct reactants; ½ mark for correct product — total 2 marks]

(b) The gas evolved is Hydrogen gas (H₂).

Ethanol reacts with sodium metal to form sodium ethoxide and hydrogen gas. Brisk effervescence is observed due to the evolution of H₂ gas.

Balanced chemical equation:

2C₂H₅OH + 2Na → 2C₂H₅ONa + H₂↑

(ethanol) (sodium ethoxide)

[Award ½ mark for identifying hydrogen gas; ½ mark for the balanced equation — total 1 mark]

(c) The two reasons are:

(i) Soap is the sodium or potassium salt of a long-chain fatty acid. It contains a carboxylate (–COONa) group. Hard water contains dissolved calcium (Ca²⁺) and magnesium (Mg²⁺) salts. Soap reacts with these ions to form an insoluble precipitate called scum (calcium or magnesium stearate), which is wasted without forming any lather. Since much of the soap is consumed in forming scum, very little is left to reduce surface tension and form lather.

(ii) Synthetic detergents contain a sulphonate (–SO₃Na) or sulphate (–OSO₃Na) group instead of a carboxylate group. The calcium and magnesium salts of sulphonates are soluble in water. Therefore, detergents do not form any insoluble scum with hard water and lather freely even in hard water, making them effective as cleaning agents.

[Award 1 mark for each reason — both must be distinct and clearly explained — total 2 marks]
Q7Case-based4 marks

Asha works in a cooking oil factory. Her job is to convert liquid vegetable oils into solid fats (vanaspati ghee) for longer shelf life. The process involves passing hydrogen gas through the liquid oil in the presence of a nickel catalyst. She also notices that when the solid fat is left exposed to air for many days, it develops a bad smell and taste. Her supervisor tells her that the solid fat has undergone a chemical change due to atmospheric oxygen. Asha's factory also makes soap. The soap is made by heating the same vegetable oil with a concentrated sodium hydroxide solution. The resulting soap is then tested in the local water supply, which is known to be hard water containing dissolved calcium and magnesium salts. The soap forms very little lather and a white, curdy substance appears instead.

Read the following passage and answer the questions that follow:

Asha works in a cooking oil factory. Her job is to convert liquid vegetable oils into solid fats (vanaspati ghee) for longer shelf life. The process involves passing hydrogen gas through the liquid oil in the presence of a nickel catalyst. She also notices that when the solid fat is left exposed to air for many days, it develops a bad smell and taste. Her supervisor tells her that the solid fat has undergone a chemical change due to atmospheric oxygen.

Asha's factory also makes soap. The soap is made by heating the same vegetable oil with a concentrated sodium hydroxide solution. The resulting soap is then tested in the local water supply, which is known to be hard water containing dissolved calcium and magnesium salts. The soap forms very little lather and a white, curdy substance appears instead.

(a) Name the type of reaction by which liquid oil is converted into solid fat in Asha's factory.
(b) Name the chemical phenomenon that causes the solid fat to develop a bad smell and taste on prolonged exposure to air.
(c) (i) Name the type of reaction used to make soap from vegetable oil and NaOH. Write a chemical equation to represent this reaction (you may use RCOOH to represent the fatty acid part of the oil).
(ii) Explain why the soap forms little lather and produces a white, curdy substance in the local hard water supply.

Show answer
(a) The type of reaction is Hydrogenation (addition reaction).
Liquid vegetable oil (unsaturated, containing C=C double bonds) reacts with hydrogen gas in the presence of nickel (Ni) as a catalyst to form solid fat (saturated compound). This is an addition reaction — hydrogen atoms add across the C=C double bond, converting it to a C–C single bond.
[1 mark]

(b) The phenomenon is Rancidity.
The solid fat undergoes oxidation by atmospheric oxygen. The unsaturated bonds present in traces, or the fat molecules themselves, react with O₂ to form products (carboxylic acids, aldehydes, ketones) that have an unpleasant smell and taste. This process is called rancidity.
[1 mark]

(c)
(i) The type of reaction used to make soap is Saponification.
In saponification, a fat or oil (ester of fatty acid and glycerol) is heated with a strong alkali (NaOH) to produce soap (sodium salt of a fatty acid) and glycerol.

Chemical equation:

RCOOC₃H₅ + 3NaOH —(Heat)→ 3RCOONa + C₃H₅(OH)₃
(fat/oil) (sodium hydroxide) (soap) (glycerol)

[1 mark for naming saponification + 1 mark for correct equation with conditions and products — award within this sub-part]

(ii) Hard water contains dissolved calcium (Ca²⁺) and magnesium (Mg²⁺) salts. Soap (sodium stearate, RCOONa) reacts with these ions to form calcium stearate or magnesium stearate, which are insoluble in water. This insoluble substance is the white, curdy precipitate called scum. Since soap is consumed in forming scum, very little soap remains to produce lather, making cleaning ineffective.

Equation for scum formation:
2RCOONa + CaCl₂ → (RCOO)₂Ca↓ + 2NaCl
(soap) (hard water) (scum — insoluble)
[1 mark]

[Total: 4 marks]
Q8Case-based4 marks

A food technology student, Priya, is working on extending the shelf life of packaged snacks. She notices that a bag of potato chips left open turns rancid within two days, while a sealed bag of the same chips stays fresh for several months. On reading the label of the sealed bag, she finds it contains 'ethyl ethanoate' as an added flavouring agent and notes that the bag is flushed with nitrogen gas before sealing. Her chemistry teacher explains that the long carbon chains in the fats present in chips are susceptible to a particular chemical change, and that the same organic chemistry principles that govern this change also explain why ethyl ethanoate can be prepared in the laboratory.

A food technology student, Priya, is working on extending the shelf life of packaged snacks. She notices that a bag of potato chips left open turns rancid within two days, while a sealed bag of the same chips stays fresh for several months. On reading the label of the sealed bag, she finds it contains 'ethyl ethanoate' as an added flavouring agent and notes that the bag is flushed with nitrogen gas before sealing. Her chemistry teacher explains that the long carbon chains in the fats present in chips are susceptible to a particular chemical change, and that the same organic chemistry principles that govern this change also explain why ethyl ethanoate can be prepared in the laboratory.

(a) Identify the chemical process by which open chips turn rancid, naming the type of reaction involved. [1 mark]

(b) State ONE reason why the sealed bag is flushed with nitrogen gas before sealing, rather than simply being sealed with air inside. [1 mark]

(c) Priya's teacher says ethyl ethanoate can be prepared from two simpler compounds.
(i) Name the two compounds required and write the balanced chemical equation for this preparation, including the catalyst and the type of reaction. [1 mark]
(ii) Priya notices that when she adds a few drops of sodium carbonate solution to a sample of one of the starting materials used in (c)(i), brisk effervescence is observed. Identify this starting material and write the balanced chemical equation for this reaction. [1 mark]

Show answer
(a) The chips turn rancid due to oxidation — the unsaturated fats and oils in the chips react with atmospheric oxygen (O₂), breaking down the C=C double bonds in the long carbon chains to form compounds with unpleasant smell and taste. This is an oxidation reaction (also called rancidity). [1 mark]

(b) Nitrogen gas is chemically inert — it does not react with the fats and oils present in the chips. Flushing with nitrogen displaces oxygen from the packet, thereby preventing the oxidation of fats. Air contains approximately 21% oxygen, which would cause rancidity even in a sealed packet; nitrogen eliminates this oxidising agent entirely. [1 mark]

(c)(i) Ethyl ethanoate is prepared from ethanol (C₂H₅OH) and ethanoic acid (CH₃COOH).

The reaction is esterification:

CH₃COOH + C₂H₅OH ⇌ CH₃COOC₂H₅ + H₂O
conc. H₂SO₄

(Conditions: conc. H₂SO₄ as catalyst and dehydrating agent, written above the reversible arrow ⇌)

This is an esterification reaction — a reversible reaction in which a carboxylic acid reacts with an alcohol to form an ester and water, in the presence of conc. H₂SO₄ as catalyst. [1 mark]

(c)(ii) The starting material that gives brisk effervescence with sodium carbonate solution is ethanoic acid (CH₃COOH) — also called acetic acid.

Observation: Brisk effervescence is observed. A colourless, odourless gas (CO₂) is evolved, which turns lime water milky.

Balanced equation:

2CH₃COOH + Na₂CO₃ → 2CH₃COONa + H₂O + CO₂↑

(Sodium carbonate reacts with ethanoic acid — a carboxylic acid — to produce sodium ethanoate, water, and carbon dioxide gas.) [1 mark]
Q9MCQ1 mark

An oxygen atom has the atomic number 8. How many valence electrons does an oxygen atom possess, and how many covalent bonds can it typically form to complete its octet?

Show answer
Option (A) is correct.

Explanation: Oxygen has atomic number 8, giving it the electronic configuration 2, 6. It therefore possesses 6 valence electrons in its outermost shell. To complete its octet, oxygen requires 2 more electrons, which it achieves by sharing electrons with other atoms — forming 2 covalent bonds. For example, in water (H₂O), oxygen forms one covalent bond with each hydrogen atom. Options (B) and (D) state incorrect valence electron counts, and Option (C) incorrectly states that 6 bonds are formed.
Q10MCQ1 mark

Which of the following functional groups is present in ethanoic acid?

Show answer
Option (c) is correct.

Explanation: Ethanoic acid (CH₃COOH) is a carboxylic acid. The functional group that defines all carboxylic acids is the carboxyl group, –COOH. Option (a) –OH is the functional group of alcohols; option (b) –CHO is the aldehyde group; option (d) –CO– is the ketone group. Since ethanoic acid belongs to the carboxylic acid family, its functional group is –COOH.
Q11MCQ1 mark

In the formation of a propyne (C₃H₄) molecule, the first and second carbon atoms are joined by a single bond, while the second and third carbon atoms are joined by a triple bond. What is the total number of electrons shared in the entire propyne molecule?

Show answer
Option (D) is correct.

Explanation: Each covalent bond involves 2 shared electrons; a triple bond involves 6 shared electrons. The structural formula of propyne is CH₃–C≡CH. Counting every bond in the molecule: the three C₁–H single bonds contribute 3 × 2 = 6 electrons; the C₁–C₂ single bond contributes 1 × 2 = 2 electrons; the C₂≡C₃ triple bond contributes 1 × 6 = 6 electrons; and the C₃–H single bond contributes 1 × 2 = 2 electrons. Total electrons shared = 6 + 2 + 6 + 2 = 16.
Q12MCQ1 mark

In a molecule of propyne (C₃H₄), the first two carbon atoms are joined by a triple bond, and the third carbon atom is bonded to the second carbon atom by a single bond. How many total electrons are shared in all the covalent bonds present in one molecule of propyne?

Show answer
Option (A) is correct.

Explanation: The structural formula of propyne is CH≡C–CH₃. Counting every covalent bond in the molecule: the triple bond between C1 and C2 consists of 3 bond pairs (6 shared electrons); the single bond between C2 and C3 consists of 1 bond pair (2 shared electrons); the C1–H bond consists of 1 bond pair (2 shared electrons); and the three C3–H bonds consist of 3 bond pairs (6 shared electrons). The total number of bond pairs = 3 + 1 + 1 + 3 = 8, giving a total of 8 × 2 = 16 shared electrons in all covalent bonds present in one molecule of propyne.
Q13MCQ1 mark

In the structure of diamond, each carbon atom is covalently bonded to four other carbon atoms in a rigid three-dimensional network. Which of the following properties of diamond is a direct consequence of this bonding arrangement?

Show answer
Option (A) is correct.

Explanation: In diamond, each carbon atom forms four strong covalent bonds with four neighbouring carbon atoms, creating a giant rigid three-dimensional tetrahedral network throughout the entire crystal. This extensive interlocking of covalent bonds makes diamond extremely hard — it is the hardest naturally occurring substance. Since all four valence electrons of every carbon atom are used in bond formation, there are no free or delocalised electrons available to carry electric charge, so diamond does not conduct electricity. Options (B) and (C) describe graphite, which has a layered structure where carbon atoms are bonded to only three others, leaving one free electron per atom that allows electrical conduction along the layers. Option (D) is incorrect because sharing electrons in covalent bonds does not produce free electrons — electrical conduction requires delocalised electrons that can move freely, which are absent in diamond.
Q14MCQ1 mark

Priya is making salad dressing in the kitchen. She adds vinegar (a dilute solution of ethanoic acid) to olive oil and shakes the bottle. She notices that the vinegar and oil do not mix even after vigorous shaking. Which property of ethanoic acid best explains why it mixes well with water but NOT with olive oil?

Show answer
Option (a) is correct. Ethanoic acid (CH₃COOH) contains a –COOH (carboxyl) functional group, which makes the molecule polar. The principle 'like dissolves like' governs solubility — polar molecules dissolve in polar solvents (such as water) and non-polar molecules dissolve in non-polar solvents (such as oils and fats). Since ethanoic acid is polar, it is miscible with water but does not dissolve in non-polar olive oil. This is why Priya observes that the two liquids separate even after shaking.
Q15MCQ1 mark

The atomic number of sulfur is 16. How many valence electrons does a sulfur atom possess, and how many covalent bonds can it typically form to complete its octet?

2
4
6
8

Show answer
Option (C) is correct.

Explanation: The atomic number of sulfur is 16, giving it the electronic configuration 2, 8, 6. The outermost (third) shell contains 6 electrons, so sulfur has 6 valence electrons. To complete its octet, sulfur requires 8 − 6 = 2 more electrons; it achieves this by sharing 2 electrons with other atoms, thereby forming 2 covalent bonds. This is illustrated in hydrogen sulphide (H₂S), where sulfur forms 2 covalent bonds with two hydrogen atoms.
Q16MCQ1 mark

In a molecule of nitrogen gas (N₂), the two nitrogen atoms are joined by a triple bond, sharing three pairs of electrons. Similarly, in a molecule of ethyne (C₂H₂), the two carbon atoms are also joined by a triple bond. How many total electrons are shared between the two carbon atoms alone in the triple bond of ethyne?

Show answer
Option (C) is correct.

Explanation: A triple bond consists of three shared pairs of electrons between the two bonded atoms. Each shared pair contains 2 electrons. In ethyne (C₂H₂), the two carbon atoms are joined by a triple bond (C≡C), so the total number of electrons shared between the two carbon atoms = 3 pairs × 2 electrons per pair = 6 electrons.
Q17MCQ1 mark

The atomic number of chlorine is 17. How many valence electrons are present in one atom of chlorine, and how many covalent bonds can it typically form to achieve a stable octet configuration?

Show answer
Option (A) is correct.

Explanation: Chlorine has atomic number 17, so its electronic configuration is 2, 8, 7 — giving it 7 valence electrons in the outermost shell. To complete its octet, chlorine requires 1 more electron; it therefore shares 1 electron with another atom, forming 1 covalent bond. Options (B), (C), and (D) are incorrect as they assign a wrong number of valence electrons or an incorrect number of covalent bonds to chlorine.
Q18MCQ1 mark

Ethyne (C₂H₂) is a hydrocarbon used in welding torches. Which of the following correctly describes the type of bond between the two carbon atoms in ethyne and the total number of shared electrons in that bond?

Show answer
Option (A) is correct.

Explanation: In ethyne (C₂H₂), each carbon atom has a valency of 4. Each carbon forms one bond with hydrogen, leaving three bonds to be shared between the two carbon atoms. This results in a triple bond (represented as C≡C) between the two carbon atoms. A triple bond consists of 3 shared pairs of electrons, giving a total of 6 shared electrons in that bond. Option (D) is incorrect because although it correctly identifies a triple bond, 3 shared electrons would imply only 1.5 pairs, which is chemically impossible — a triple bond always involves 3 complete pairs, i.e. 6 electrons.
Q19MCQ1 mark

A carbon compound contains 2 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom in its molecular formula. The compound belongs to the homologous series of alcohols. Identify the IUPAC name of this compound.

Show answer
Option (A) is correct.

Explanation: The molecular formula of the compound is C₂H₆O. Alcohols belong to the homologous series with the general formula CₙH₂ₙ₊₁OH. For n = 2, the formula is C₂H₅OH, which gives the molecular formula C₂H₆O — this matches exactly. The IUPAC name is formed by taking the prefix for 2 carbon atoms (eth-) and adding the alcohol suffix (-anol), giving ethanol. The remaining options are eliminated as follows: methanol is CH₃OH (C₁H₄O, n = 1); propanol is C₃H₇OH (C₃H₈O, n = 3); ethanoic acid is CH₃COOH (C₂H₄O₂), which belongs to the carboxylic acid series, not the alcohol series, and contains 2 oxygen atoms.
Q20MCQ1 mark

A student is given two colourless liquids, P and Q. The following observations are recorded:
• Liquid P has a pungent, sour smell and turns blue litmus paper red.
• When P is added to solid sodium hydrogen carbonate, brisk effervescence is observed and the gas produced turns lime water milky.
• Liquid Q is neutral (no effect on litmus), burns with a blue flame, and does not react with sodium hydrogen carbonate.
• When P and Q are heated together in the presence of concentrated H₂SO₄, a sweet-smelling liquid R is produced.
• When R is treated with aqueous NaOH solution on heating, P and Q are regenerated.

Which of the following correctly identifies P, Q, and R, AND correctly names the reaction that converts R back to P and Q?

Show answer
Option (a) is correct.

Explanation: The observations must be analysed step by step to identify each substance.

Identifying P: P turns blue litmus red (acidic), reacts with NaHCO₃ to give CO₂ gas (turns lime water milky) — this confirms P contains the –COOH (carboxylic acid) functional group. The pungent, sour smell is characteristic of ethanoic acid (CH₃COOH). The reaction is: CH₃COOH + NaHCO₃ → CH₃COONa + H₂O + CO₂↑

Identifying Q: Q is neutral (no effect on litmus), burns with a blue flame (organic compound, complete combustion), and does not react with NaHCO₃ — this rules out a carboxylic acid. Q reacts with P (an acid) in the presence of conc. H₂SO₄ to form a sweet-smelling product — this is the hallmark of esterification. Q must contain the –OH (hydroxyl) functional group, identifying it as ethanol (C₂H₅OH). (Ethanol is neutral and does not react with NaHCO₃, unlike ethanoic acid.)

Identifying R: The reaction of ethanoic acid (P) with ethanol (Q) in the presence of conc. H₂SO₄ produces ethyl ethanoate (CH₃COOC₂H₅) — a sweet-smelling ester. This is esterification:
CH₃COOH + C₂H₅OH ⇌ (conc. H₂SO₄, Heat) CH₃COOC₂H₅ + H₂O

Naming the reverse reaction: When R (ethyl ethanoate) is treated with aqueous NaOH on heating, the ester is hydrolysed to regenerate the sodium salt of the acid and the alcohol. This is called saponification (alkaline hydrolysis of an ester):
CH₃COOC₂H₅ + NaOH → (Heat) CH₃COONa + C₂H₅OH

Why the other options are wrong:
• Option (b) is incorrect because P is acidic (turns litmus red, reacts with NaHCO₃) — it cannot be ethanol, which is neutral.
• Option (c) is incorrect because R is ethyl ethanoate (formed from 2-carbon acid + 2-carbon alcohol), not methyl ethanoate (which would require methanol).
• Option (d) is incorrect because the reverse reaction is saponification (alkaline hydrolysis), not hydrogenation. Hydrogenation involves addition of H₂ across a C=C double bond and is unrelated to ester hydrolysis.
Q21MCQ1 mark

A carbon compound contains 2 carbon atoms, 6 hydrogen atoms, and 1 oxygen atom in its molecular formula. The compound belongs to the homologous series of alcohols. Identify the compound.

Show answer
Option (B) is correct.

Explanation: The molecular formula of the compound is C₂H₆O. Alcohols belong to the homologous series with the general formula CₙH₂ₙ₊₂O (or CₙH₂ₙ₊₁OH), where the functional group is –OH. For n = 2, the formula gives C₂H₆O, which corresponds to ethanol (CH₃CH₂OH). Methanol has the formula CH₃OH (C₁H₄O), ethanoic acid has the formula CH₃COOH (C₂H₄O₂), and propanol has the formula C₃H₇OH (C₃H₈O) — none of these match the given molecular formula. Therefore, the compound is ethanol.
Q22MCQ1 mark

The melting point of pure ethanoic acid is 290 K. Based on this fact, which of the following statements is correct about ethanoic acid?

Show answer
Option (A) is correct.

Explanation: Pure ethanoic acid (CH₃COOH) has a melting point of 290 K, which is just below typical room temperature. In cold climates, where temperatures fall to or below 290 K, pure ethanoic acid freezes into an ice-like solid. Because of this freezing behaviour, pure ethanoic acid is commonly known as glacial acetic acid. Options (B), (C), and (D) are incorrect as the melting point of a substance is not related to its boiling point, decomposition, or polymerisation.
Q23MCQ1 mark

In the allotrope of carbon known as graphite, each carbon atom is bonded to how many other carbon atoms, and what type of bonding holds the layers together?

Diagram for question 23: Carbon and its Compounds
Show answer
Option (A) is correct.

Explanation: In graphite, each carbon atom forms three covalent bonds with three neighbouring carbon atoms within the same layer, creating a planar hexagonal network. The fourth valence electron of each carbon atom remains delocalised between the layers, which is why graphite conducts electricity. The layers themselves are held together only by weak van der Waals forces, not covalent bonds, which allows the layers to slide over one another — making graphite soft and suitable as a lubricant. Option (B) is incorrect because four covalent bonds between carbon atoms in a tetrahedral 3D arrangement describes diamond, not graphite. Option (C) is incorrect because carbon forms covalent bonds, not ionic bonds, and each carbon in graphite bonds to three, not two, other carbon atoms. Option (D) is incorrect because although each carbon atom does bond to three others, the interlayer forces in graphite are weak van der Waals forces, not strong covalent bonds.
Q24MCQ1 mark

Buckminsterfullerene (C₆₀) is an allotrope of carbon in which each carbon atom is covalently bonded to exactly three other carbon atoms, forming a hollow spherical structure. Which of the following statements correctly describes a property of Buckminsterfullerene that distinguishes it from both diamond and graphite?

Diagram for question 24: Carbon and its Compounds
Show answer
Option (A) is correct.

Explanation: Buckminsterfullerene (C₆₀) is an allotrope of carbon in which 60 carbon atoms are arranged in a hollow spherical cage-like structure consisting of 12 pentagons and 20 hexagons, resembling a football. This structure is unique to C₆₀ and distinguishes it from both diamond and graphite. Option (B) describes diamond, in which each carbon atom forms four covalent bonds in a three-dimensional tetrahedral network, making it the hardest natural substance. Option (C) describes graphite, in which carbon atoms form flat hexagonal layers with one free valence electron per atom that is responsible for its electrical conductivity. Option (D) is incorrect as it describes bonding between carbon and hydrogen atoms, which is characteristic of hydrocarbons, not an allotrope of pure carbon.
Q25MCQ1 mark

In a molecule of ethene (C₂H₄), the two carbon atoms are joined by a double bond, and each carbon atom is also bonded to two hydrogen atoms. Which of the following correctly states the total number of single bonds and double bonds present in one molecule of ethene respectively?

Show answer
Option (A) is correct.

Explanation: In ethene (C₂H₄), the two carbon atoms are joined by one C=C double bond. Each carbon atom is also bonded to two hydrogen atoms, giving 2 + 2 = 4 C–H single bonds in total. Counting all bonds: there are 4 single bonds (all C–H) and 1 double bond (C=C), which matches option (A).
Q26MCQ1 mark

A student is given five carbon compounds with the following molecular formulae:
(i) C₂H₄ (ii) C₃H₆ (iii) C₄H₈ (iv) C₅H₁₀ (v) C₆H₁₄

The student adds bromine water to each compound. Which of the following conclusions is CORRECT?

Show answer
Option (c) is correct.

Explanation: Bromine water is decolourised by unsaturated compounds — those containing a C=C double bond — through an addition reaction: C=C + Br₂ → C–C(Br)–C(Br). Compounds (i) C₂H₄, (ii) C₃H₆, (iii) C₄H₈, and (iv) C₅H₁₀ all follow the general formula CₙH₂ₙ, which is the formula for alkenes (one C=C double bond). Each of these will undergo addition with bromine water and decolourise it. Compound (v) C₆H₁₄ follows the general formula CₙH₂ₙ₊₂, which is the formula for alkanes — fully saturated hydrocarbons with no double bonds. Alkanes undergo substitution reactions (not addition) and do NOT decolourise bromine water under normal conditions. Therefore, only compound (v) fails to decolourise bromine water.
Q27MCQ1 mark

A student draws the structural skeleton of a five-carbon compound. How many structurally different carbon skeletons are possible for an alkane with five carbon atoms (C₅H₁₂)?

Diagram for question 27: Carbon and its Compounds
Show answer
Option (B) is correct.

Explanation: For an alkane with five carbon atoms (C₅H₁₂), exactly three structurally different carbon skeletons are possible. The first is n-pentane, a straight chain of five carbons (C–C–C–C–C). The second is 2-methylbutane (isopentane), in which a four-carbon chain carries one –CH₃ branch on the second carbon. The third is 2,2-dimethylpropane (neopentane), in which a central carbon is bonded to four –CH₃ groups. No other arrangement of five carbons gives a distinct skeleton; any other attempt either repeats one of these three or violates the tetravalency of carbon. Therefore, the total number of structurally different carbon skeletons for C₅H₁₂ is 3.
Q28MCQ1 mark

In a molecule of acetic acid (CH₃COOH), the carbon atoms, hydrogen atoms, and oxygen atoms are held together by covalent bonds. How many single bonds and double bonds are present in one molecule of acetic acid respectively?

Diagram for question 28: Carbon and its Compounds
Show answer
Option (B) is correct.

Explanation: The structural formula of acetic acid is CH₃–C(=O)–OH. Counting all bonds systematically: the CH₃ group contributes 3 C–H single bonds; the C–C bond between the methyl carbon and the carboxyl carbon gives 1 single bond; the carboxyl group contains 1 C=O double bond, 1 C–O single bond (to the –OH), and 1 O–H single bond. This gives a total of 3 + 1 + 1 + 1 = 6 single bonds and 1 double bond, which matches option (B).
Q29MCQ1 mark

How many valence electrons are present in a phosphorus atom ³¹₁₅P, and how does this compare to the number of covalent bonds carbon (tetravalent) can form?

Show answer
Option (A) is correct.

Explanation: Phosphorus has atomic number 15, giving it the electronic configuration 2, 8, 5; it therefore has 5 valence electrons in its outermost shell. Carbon is tetravalent — it has 4 valence electrons and forms exactly 4 covalent bonds with other atoms. Option (A) correctly states both facts, while the remaining options either assign an incorrect valence electron count to phosphorus or an incorrect number of covalent bonds to carbon.
Q30MCQ1 mark

In the diamond allotrope of carbon, each carbon atom forms covalent bonds with four other carbon atoms. Which of the following correctly explains why diamond is an extremely hard substance?

Show answer
Option (B) is correct.

Explanation: In diamond, each carbon atom forms four strong covalent bonds with four neighbouring carbon atoms in a tetrahedral arrangement, creating a rigid three-dimensional network structure that extends throughout the entire crystal lattice. Because every atom is locked into this continuous covalent framework, an enormous amount of energy is required to break or deform the structure, which accounts for diamond's exceptional hardness. Option (A) is incorrect because the bonds are not loose — each carbon uses all four valence electrons to form strong sigma bonds. Option (C) describes graphite, where carbon atoms form flat hexagonal layers held together by weak van der Waals forces, not diamond. Option (D) is incorrect because diamond has no free electrons and no metallic bonding; it is in fact a non-conductor of electricity.

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Carbon and its Compounds Class 10 Science Questions