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NCERT SolutionsClass 11 Chemistry
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NCERT Solutions
Class 11 Chemistry

9 chapters · 47 important questions · Updated 2025-26

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Ch 1

Some Basic Concepts of Chemistry

This chapter lays the quantitative foundation of chemistry by introducing the mole concept, atomic and molecular masses, and stoichiometry. Students learn to calculate empirical and molecular formulae from percentage composition data. Laws of chemical combination — conservation of mass, definite proportions, multiple proportions, and Gay-Lussac's law — are thoroughly covered. Molar volume, Avogadro's number, and limiting reagent calculations form the core of this chapter.

Key Topics

Laws of chemical combination: Law of Conservation of Mass, Law of Definite Proportions, Law of Multiple ProportionsDalton's Atomic Theory and its postulatesAtomic mass, molecular mass, and formula massMole concept: 1 mol = 6.022 × 10²³ particles; molar mass in g/molEmpirical and molecular formula from % compositionStoichiometry and stoichiometric calculationsLimiting reagent and percentage yieldMolarity (M = n/V) and molality (m = n/w in kg)

Important Questions

Q1

Calculate the empirical and molecular formula of a compound containing 40% carbon, 6.67% hydrogen, and 53.33% oxygen. Its molar mass is 60 g/mol.

Long Answer3M
Q2

State the Law of Conservation of Mass. In a reaction, 1.6 g of CH₄ burns completely in oxygen. Calculate the mass of CO₂ and H₂O formed.

Long Answer3M
Q3

Calculate the number of molecules and atoms in 5.6 L of CO₂ at STP.

Short Answer2M
Q4

0.5 mol of H₂ reacts with 0.5 mol of O₂ to form water. Identify the limiting reagent and calculate the mass of water formed.

Long Answer3M
Q5

What is the molarity of a solution prepared by dissolving 5.85 g of NaCl (Molar mass = 58.5 g/mol) in 500 mL of water?

Short Answer2M
Ch 2

Structure of Atom

This chapter traces the evolution of atomic models from Thomson's plum-pudding model through Rutherford's nuclear model to Bohr's model and the quantum mechanical model. Quantum numbers, the aufbau principle, Pauli exclusion principle, and Hund's rule govern electronic configurations. The dual nature of matter (de Broglie relation) and Heisenberg's uncertainty principle are key modern concepts. Students must also understand hydrogen spectrum line series (Lyman, Balmer, Paschen).

Key Topics

Thomson's, Rutherford's, and Bohr's atomic models — observations and limitationsBohr's equation: Eₙ = −13.6/n² eV; rₙ = 0.529n² Å (for H)Quantum numbers: n (principal), l (azimuthal), mₗ (magnetic), ms (spin)Aufbau principle, Pauli Exclusion Principle, Hund's Rule of Maximum Multiplicityde Broglie relation: λ = h/mvHeisenberg's Uncertainty Principle: Δx · Δp ≥ h/4πElectronic configuration — notation and orbital filling orderHydrogen spectrum: Lyman (UV), Balmer (visible), Paschen, Brackett, Pfund series

Important Questions

Q1

State Heisenberg's Uncertainty Principle. If the velocity of an electron is 2.2 × 10⁶ m/s with uncertainty of 0.001%, calculate the uncertainty in its position.

Long Answer3M
Q2

Write the electronic configuration of Cr (Z=24) and Cu (Z=29) and explain why they are exceptions to the Aufbau principle.

Long Answer3M
Q3

Calculate the wavelength of the electron moving with a velocity of 2.05 × 10⁷ m/s. (h = 6.626 × 10⁻³⁴ J·s; mₑ = 9.1 × 10⁻³¹ kg)

Short Answer2M
Q4

Explain Bohr's model of the hydrogen atom. What are its two main limitations?

Long Answer4M
Q5

How many electrons in an atom can have n = 3? Write all the subshells and the number of orbitals in each.

Short Answer2M
Ch 3

Classification of Elements and Periodicity in Properties

This chapter covers the historical development of periodic classification from Döbereiner's triads to Mendeleev's table to the modern long form of the periodic table. Students study periodic trends in atomic radius, ionic radius, ionisation enthalpy, electron gain enthalpy, and electronegativity. The concept of effective nuclear charge (Zeff) and shielding is central to explaining all periodic trends. Anomalous properties of second-period elements and diagonal relationships are important for board exams.

Key Topics

Mendeleev's periodic law vs Modern periodic lawStructure of the modern periodic table: periods, groups, s/p/d/f blocksAtomic radius: covalent radius and van der Waals radius; trend across period and down groupIonisation enthalpy (IE₁ and IE₂): trend and exceptions (Be vs B; N vs O)Electron gain enthalpy: trend and anomaly (Cl > F)Electronegativity: Pauling scale; trend across period and down groupEffective nuclear charge (Zeff) and shielding effectDiagonal relationships (Li–Mg, Be–Al, B–Si)

Important Questions

Q1

The first ionisation enthalpies of B, C, N, O are 800, 1086, 1402, 1314 kJ/mol respectively. Why is the IE₁ of O less than that of N?

Long Answer3M
Q2

Arrange F, Cl, Br, I in increasing order of (i) atomic radius and (ii) electron gain enthalpy, with justification.

Long Answer3M
Q3

What is the diagonal relationship? Explain with the example of Li and Mg.

Short Answer2M
Q4

Define ionisation enthalpy. How does it vary along a period and down a group? Give reasons.

Long Answer4M
Q5

Write the number of elements in (i) 1st period, (ii) 2nd period, (iii) 4th period of the modern periodic table.

Short Answer1M
Ch 4

Chemical Bonding and Molecular Structure

This chapter explains why and how atoms combine to form molecules using the octet rule, ionic bonding, covalent bonding, and VSEPR theory. Valence Bond Theory (VBT) introduces orbital overlap and hybridisation (sp, sp², sp³, sp³d, sp³d²), while Molecular Orbital Theory (MOT) describes bonding in terms of BMOs and ABMOs. Resonance, formal charge, dipole moment, and the properties of ionic and covalent compounds are important exam topics.

Key Topics

Kössel–Lewis approach: octet rule, Lewis dot structures, formal chargeIonic bond: formation, lattice energy, Born–Haber cycle conceptCovalent bond: VBT — sigma (σ) and pi (π) bondsVSEPR theory: predicting geometry (linear, trigonal planar, tetrahedral, trigonal bipyramidal, octahedral)Hybridisation: sp (BeCl₂), sp² (BF₃), sp³ (CH₄/NH₃/H₂O), sp³d (PCl₅), sp³d² (SF₆)Resonance: O₃, CO₃²⁻, SO₂; resonance energyMOT: bonding order = (Nb − Na)/2; paramagnetic O₂, diamagnetic N₂Dipole moment; polarity of molecules; hydrogen bond (inter and intra)

Important Questions

Q1

Predict the shapes of PCl₅ and SF₆ using VSEPR theory. State the hybridisation of the central atom in each.

Long Answer3M
Q2

Draw Lewis structures of CO₂, SO₃, and NO₃⁻. Indicate formal charges wherever applicable.

Long Answer3M
Q3

Explain why NH₃ has a higher boiling point than PH₃.

Short Answer2M
Q4

On the basis of Molecular Orbital Theory, predict the bond order and magnetic nature of O₂ and O₂²⁻.

Long Answer4M
Q5

Why is the H–O–H bond angle in water 104.5° and not 109.5°?

Short Answer2M
Q6

What is resonance? Explain with the structure of SO₂.

Short Answer2M
Ch 5

Thermodynamics

This chapter applies the laws of thermodynamics to chemical reactions, defining internal energy, enthalpy, and entropy as state functions. The first law (ΔU = q + w) and Hess's law of constant heat summation are foundational. Standard enthalpies of formation, combustion, atomisation, bond dissociation, and solution/hydration are covered in depth. The second law introduces entropy and spontaneity; the Gibbs free energy equation (ΔG = ΔH − TΔS) determines whether a reaction is spontaneous.

Key Topics

System, surroundings, state functions; intensive vs extensive propertiesFirst Law of Thermodynamics: ΔU = q + w; work = −PΔV for expansionEnthalpy: H = U + PV; ΔH = ΔU + ΔngRTHess's Law of Constant Heat SummationStandard enthalpy of formation (ΔfH°), combustion (ΔcH°), atomisation, bond dissociationEntropy (S) — measure of disorder; second law: ΔS_universe > 0 for spontaneous processGibbs free energy: ΔG = ΔH − TΔS; spontaneity at ΔG < 0Relationship between ΔG° and equilibrium constant K: ΔG° = −RT ln K

Important Questions

Q1

Using Hess's law, calculate the standard enthalpy of formation of CH₄(g) given that: C(s) + O₂(g) → CO₂(g), ΔH° = −393.5 kJ/mol; H₂(g) + ½O₂(g) → H₂O(l), ΔH° = −285.8 kJ/mol; CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(l), ΔH° = −890.4 kJ/mol.

Long Answer5M
Q2

For the reaction N₂(g) + 3H₂(g) → 2NH₃(g), ΔH° = −92 kJ/mol. Calculate ΔU° at 27°C. (R = 8.314 J mol⁻¹ K⁻¹)

Long Answer3M
Q3

Predict the sign of ΔS for the following reactions: (i) CaCO₃(s) → CaO(s) + CO₂(g); (ii) 2SO₂(g) + O₂(g) → 2SO₃(g). Give reasons.

Short Answer2M
Q4

For a reaction ΔH = +ve and ΔS = +ve. At what temperature will the reaction be spontaneous? Justify using ΔG = ΔH − TΔS.

Long Answer3M
Q5

What is the relationship between standard Gibbs free energy change (ΔG°) and the equilibrium constant K? If ΔG° < 0, what does this imply about K?

Short Answer2M
Ch 6

Equilibrium

This chapter examines both chemical and ionic equilibrium. For chemical equilibrium, the law of mass action gives the equilibrium constant expression (Kc and Kp), and Le Chatelier's principle predicts how equilibrium shifts on changing concentration, pressure, or temperature. Ionic equilibrium covers Arrhenius, Brønsted–Lowry, and Lewis definitions of acids and bases, pH, the ionic product of water (Kw), Ka, Kb, and their relationship pKa + pKb = pKw, as well as buffer solutions and the Henderson–Hasselbalch equation.

Key Topics

Law of mass action: Kc = [products]/[reactants] (equilibrium expression)Relation between Kp and Kc: Kp = Kc(RT)^ΔngLe Chatelier's Principle — effect of concentration, pressure, and temperatureBrønsted–Lowry acid–base theory; conjugate acid–base pairsIonic product of water: Kw = [H⁺][OH⁻] = 1 × 10⁻¹⁴ at 25°CpH = −log[H⁺]; pKa + pKb = 14Buffer solutions: Henderson–Hasselbalch equation pH = pKa + log([A⁻]/[HA])Solubility product (Ksp) and the common ion effect

Important Questions

Q1

For the equilibrium H₂(g) + I₂(g) ⇌ 2HI(g), Kc = 57.0 at 700 K. If 0.5 mol H₂ and 0.5 mol I₂ are placed in a 1 L container, find the equilibrium concentrations.

Long Answer5M
Q2

State Le Chatelier's Principle. How will increasing pressure affect the equilibrium N₂(g) + 3H₂(g) ⇌ 2NH₃(g)?

Long Answer3M
Q3

Calculate the pH of a 0.01 M HCl solution and a 0.001 M NaOH solution.

Short Answer2M
Q4

What is a buffer solution? Calculate the pH of a buffer containing 0.1 M acetic acid and 0.1 M sodium acetate. (pKa of acetic acid = 4.74)

Long Answer3M
Q5

Derive the relationship Kp = Kc(RT)^Δng. For which reactions is Kp = Kc?

Long Answer3M
Ch 7

Redox Reactions

This chapter develops the concept of oxidation and reduction in terms of electron transfer and changes in oxidation number. Students learn to assign oxidation states systematically and to balance redox equations by both the oxidation number method and the ion-electron (half-reaction) method. The electrochemical series and the concept of reducing and oxidising agents, disproportionation reactions, and comproportionation are also covered.

Key Topics

Classical concept: oxidation (gain of O / loss of H) and reduction (loss of O / gain of H)Electronic concept: oxidation (loss of e⁻), reduction (gain of e⁻); oxidising and reducing agentsOxidation number rules: assignment in compounds and ionsBalancing redox equations — oxidation number methodBalancing redox equations — ion-electron (half-reaction) method in acidic/basic mediumDisproportionation reactions (same element oxidised and reduced)Electrochemical series and its applications (reactivity, displacement reactions)

Important Questions

Q1

Balance the following redox equation by the ion-electron method in acidic medium: MnO₄⁻ + Fe²⁺ → Mn²⁺ + Fe³⁺

Long Answer5M
Q2

Assign oxidation numbers to each element in the following: (i) K₂Cr₂O₇, (ii) Na₂S₂O₃, (iii) H₂SO₅.

Long Answer3M
Q3

Identify the oxidising agent and reducing agent in the reaction: Zn + CuSO₄ → ZnSO₄ + Cu. Justify.

Short Answer2M
Q4

What is a disproportionation reaction? Give one example and identify the element that is simultaneously oxidised and reduced.

Short Answer2M
Q5

Balance by oxidation number method: HNO₃ (dil.) + Cu → Cu(NO₃)₂ + NO + H₂O.

Long Answer3M
Ch 8

Organic Chemistry – Some Basic Principles and Techniques

This chapter introduces the principles of organic chemistry: classification of organic compounds, IUPAC nomenclature, types of organic reactions, reaction intermediates (carbocations, carbanions, free radicals, carbenes), electronic effects (inductive, mesomeric/resonance, hyperconjugation), and methods of purification. Qualitative analysis — detection of C, H, N, S, and halogens (Lassaigne's test) — and quantitative analysis (Dumas, Kjeldahl methods) are also covered.

Key Topics

IUPAC nomenclature: rules for naming alkanes, alkenes, alkynes, and functional group compoundsHomolytic vs heterolytic fission; electrophiles and nucleophilesReaction intermediates: carbocations (stability: 3° > 2° > 1°), carbanions, free radicalsInductive effect (+I and −I) and its applicationsResonance/mesomeric effect (+M and −M) — delocalisation of electronsHyperconjugation (Baker–Nathan effect) — stabilisation of alkenes and carbocationsPurification methods: distillation, recrystallisation, sublimation, chromatographyLassaigne's test: detection of N, S, halogens; Kjeldahl's method for % nitrogen

Important Questions

Q1

Name the following compounds using IUPAC rules: (i) CH₃CH(OH)CH₂CHO; (ii) (CH₃)₃CCl; (iii) CH₂=CHCH₂CH₃.

Short Answer3M
Q2

Explain the inductive effect. Using the inductive effect, compare the acidity of formic acid and acetic acid.

Long Answer3M
Q3

What is hyperconjugation? How does it explain the stability of alkenes with greater substitution?

Long Answer3M
Q4

Describe Lassaigne's test for the detection of nitrogen in an organic compound. Write the relevant chemical equations.

Long Answer4M
Q5

Arrange the following carbocations in decreasing order of stability: (CH₃)₃C⁺, CH₃CH⁺CH₃, CH₃CH₂CH₂⁺.

Short Answer2M
Ch 9

Hydrocarbons

This chapter systematically covers the chemistry of alkanes, alkenes, alkynes, and aromatic hydrocarbons. Alkane reactions include free-radical halogenation (mechanism in steps); alkene reactions include electrophilic addition (Markovnikov's rule, anti-Markovnikov addition via HBr/peroxide), ozonolysis, and oxidation. Alkynes form acidic H due to sp hybridisation. Benzene's aromaticity (Hückel's 4n+2 rule), electrophilic aromatic substitution (EAS — halogenation, nitration, sulphonation, Friedel-Crafts), and conformations (Sawhorse and Newman) of alkanes are key topics.

Key Topics

Free-radical halogenation of alkanes: initiation, propagation, termination stepsElectrophilic addition to alkenes: mechanism; Markovnikov's ruleAnti-Markovnikov addition (peroxide/Kharasch effect) — HBr onlyOzonolysis of alkenes and alkynesAcidity of terminal alkynes (sp C–H); reactions with Na, NaNH₂Aromaticity: Hückel's rule (4n+2 π electrons); benzene structureElectrophilic Aromatic Substitution (EAS): nitration, halogenation, sulphonation, Friedel–Crafts alkylation/acylationConformations of ethane: staggered (Newman) and eclipsed forms

Important Questions

Q1

Explain the mechanism of electrophilic addition of HBr to propene. What product is predominantly formed and why (Markovnikov's rule)?

Long Answer4M
Q2

Give the mechanism of free-radical chlorination of methane. Name the three steps.

Long Answer4M
Q3

What is Markovnikov's rule? How is it violated in the presence of peroxides? Give the product of HBr addition to propene with and without peroxide.

Long Answer3M
Q4

Explain the mechanism of nitration of benzene. What is the electrophile involved?

Long Answer4M
Q5

Draw the Newman projection of the staggered and eclipsed conformations of ethane and compare their stability.

Long Answer3M
Q6

Why are terminal alkynes more acidic than alkenes? Explain in terms of hybridisation.

Short Answer2M

Frequently Asked Questions

Is NCERT enough for CBSE Class 11 Chemistry board exam?

Yes. CBSE board exams are designed entirely around NCERT. 80–90% of questions in the Class 11 Chemistry paper are directly based on NCERT concepts — sometimes reworded, never from outside NCERT. Completing all 47 important questions listed here is the minimum you need.

How to study NCERT Class 11 Chemistry for board exams?

Go chapter-by-chapter. Read the chapter first, then attempt the important questions without looking at answers. Check your answer structure — CBSE gives marks per point, so structure matters as much as content. For 5-mark answers: brief intro + 4–5 numbered points with keywords + conclusion.

Which chapters are most important in Class 11 Chemistry for CBSE boards?

Chapters with the most long-answer (5-mark) important questions carry the most marks in the board paper. Look at which chapters here have the highest question count — those are the ones CBSE has historically focused on. Don't skip any chapter, but spend extra time on these.

How many questions come from NCERT in CBSE Class 11 Chemistry exam?

Nearly all 47 questions in the Class 11 Chemistry board paper are rooted in NCERT. The exact question may be reworded, but the concept, definition, or formula always comes from the NCERT textbook. Practicing these 47 important questions covers the vast majority of what can be asked.

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