Study 2 AI-Predicted Sets. Score Your Best in TS SSC Advanced Supplementary.
Every high-probability question. Every step-by-step answer. Designed for TS SSC Advanced Supplementary Exam — June 5–12, 2026.
TS SSC Advanced Supplementary — June 5–12, 2026
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- Answers written as per TS SSC marking scheme — write this, get full marks
- Questions ranked by exam frequency (AI-analysed from TS SSC papers)
- High-prob: Quadratic Equations, Coord Geometry, Statistics
- AI-revealed high, medium and low probability questions
- Pattern recognition across 10 years of TS SSC papers
- 2 AI predicted Sets — instant access after purchase
- Answers written as per TS SSC marking scheme — write this, get full marks
- Questions ranked by exam frequency (AI-analysed from TS SSC papers)
- High-prob: Electricity, Light — Reflection & Refraction, Chemical Reactions
- AI-revealed high, medium and low probability questions
- Pattern recognition across 10 years of TS SSC papers
- 2 AI predicted Sets — instant access after purchase
1,800+ TS SSC students already preparing
Sample — see what you get
These question types appear in TS SSC papers year after year. Study all 2 AI-predicted sets and you have covered everything needed to score your best.
Q. A train travels 300 km at a constant speed. If the speed were increased by 5 km/h, the journey would take 2 hours less. Find the original speed of the train.
Appears frequently in past TS SSC board exams
Write this answer → Examiner must give full marks
Every solution follows the TS SSC official marking scheme — the same guide your examiner uses to check your paper.
Step 1
Let original speed = x km/h. Time at original speed = 300/x hours. Time at increased speed = 300/(x+5) hours.
Step 2
Equation: 300/x − 300/(x+5) = 2. Cross-multiply: 300(x+5) − 300x = 2x(x+5)
Step 3
1500 = 2x² + 10x → x² + 5x − 750 = 0. Factor: (x + 30)(x − 25) = 0
Answer
Since speed must be positive, x = 25. Original speed of the train = 25 km/h ✓
Q. State Ohm's Law. Three resistors of 4 Ω, 6 Ω, and 12 Ω are connected in parallel. Find the equivalent resistance of the combination.
Appears frequently in past TS SSC board exams
Write this answer → Examiner must give full marks
Every solution follows the TS SSC official marking scheme — the same guide your examiner uses to check your paper.
Ohm's Law
The current through a conductor is directly proportional to the potential difference across its ends, at constant temperature. V = IR.
Formula
For resistors in parallel: 1/R = 1/R₁ + 1/R₂ + 1/R₃
Calculation
1/R = 1/4 + 1/6 + 1/12 = 3/12 + 2/12 + 1/12 = 6/12 = 1/2
Answer
Equivalent resistance R = 2 Ω ✓
How it works
We studied 10 years of TS SSC papers
Every question from every past TS SSC Class 10 exam, analysed in one place.
We found what repeats every year
Each concept is ranked — high, medium or low probability for the Advanced Supplementary exam.
Your child studies only what matters
Important questions with step-by-step answers and AI predicted Sets — instant access after purchase.
Chapters that come every year
Based on 10 years of TS SSC Class 10 board papers
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Common questions
We studied 10 years of TS SSC question papers and found which concepts and question types repeat every year. We rank them high, medium or low probability — so you know exactly what to focus on.
The TS SSC Advanced Supplementary exam is for Class 10 students who did not clear the main TS SSC exam or want to improve their score. It is conducted by BSE Telangana and follows the same syllabus and question pattern as the main exam.
The TS SSC Advanced Supplementary exam 2026 is scheduled from June 5 to June 12, 2026. Mathematics and Science papers will be held during this period.
Instant access to all important questions with step-by-step answers written exactly as per the TS SSC marking scheme. Write the answer exactly as shown — get full marks. Questions are ranked by how likely they are to come. AI predicted Sets also included.
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