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CBSE · Class 11 · Chemistry

Chemistry Formula Sheet

42 formulas across 5 chapters — with variables explained and exam tips where needed.

Ch 1Basic Concepts of Chemistry(8 formulas)

Number of moles

mol

n = m/M

m = mass (g), M = molar mass (g/mol)

Number of particles

N = n × Nₐ

Nₐ = 6.022×10²³ mol⁻¹ (Avogadro's number)

Molarity

mol/L

M = n_solute / V_solution(L)

Mole fraction

χ_A = n_A / (n_A + n_B + ...)

Parts per million

ppm = (mass of solute / mass of solution) × 10⁶

Percentage yield

% yield = (actual yield / theoretical yield) × 100

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Theoretical yield is based on limiting reagent

Limiting reagent identification

Divide moles of each reactant by its stoichiometric coefficient — smallest ratio → limiting reagent

Empirical formula steps

% → g (assume 100g) → mol (÷M) → simple ratio → empirical formula

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Multiply ratios to get whole numbers if needed

Ch 5States of Matter(8 formulas)

Ideal gas law

PV = nRT

R = 0.0821 L·atm/mol·K = 8.314 J/mol·K

Combined gas law

P₁V₁/T₁ = P₂V₂/T₂

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If one variable is constant, simplify accordingly

Boyle's law

PV = constant (at constant T, n)

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P₁V₁ = P₂V₂

Charles's law

V/T = constant (at constant P, n)

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V₁/T₁ = V₂/T₂ — use Kelvin

van der Waals equation

(P + an²/V²)(V − nb) = nRT

a = intermolecular attraction, b = volume excluded per mole

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Corrects for real gas behaviour

Graham's law of effusion

r₁/r₂ = √(M₂/M₁)

r = rate of effusion, M = molar mass

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Lighter gas effuses faster

Average kinetic energy

KE_avg = 3/2 RT (per mole) or 3/2 kT (per molecule)

RMS speed

m/s

u_rms = √(3RT/M)

Ch 6Thermodynamics(8 formulas)

Relation between ΔH and ΔU

ΔH = ΔU + Δn_g RT

Δn_g = moles of gaseous products − moles of gaseous reactants

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For reactions with no gas: ΔH ≈ ΔU

Hess's law

ΔH_reaction = Σ ΔH_products − Σ ΔH_reactants (using standard enthalpies)

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Enthalpy is a state function — path doesn't matter

Bond enthalpy method

ΔH_rxn = Σ BE(bonds broken) − Σ BE(bonds formed)

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Energy is absorbed to break bonds and released to form bonds

Gibbs free energy

ΔG = ΔH − TΔS

T = temperature in K, ΔS = entropy change

Spontaneity condition

ΔG < 0 → spontaneous | ΔG = 0 → equilibrium | ΔG > 0 → non-spontaneous

Standard Gibbs energy and cell EMF

ΔG° = −nFE°

n = moles of electrons, F = 96485 C/mol

ΔG and equilibrium constant

ΔG° = −RT lnK

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K > 1 → ΔG° < 0 → products favoured

First law of thermodynamics

ΔU = Q + W (IUPAC sign convention)

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Note: W = −PΔV; work done ON system is positive

Ch 7Equilibrium(10 formulas)

Equilibrium constant Kc

Kc = [products]^stoich / [reactants]^stoich (at equilibrium)

Equilibrium constant Kp

Kp = Kc(RT)^Δn_g

R = 0.0821 L·atm/mol·K, T in K

Ionic product of water

Kw = [H⁺][OH⁻] = 1×10⁻¹⁴ at 25°C

Acid dissociation constant

Ka = [H⁺][A⁻] / [HA]

Base dissociation constant

Kb = [BH⁺][OH⁻] / [B]

Relation Ka × Kb

Ka × Kb = Kw (conjugate acid-base pair)

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Stronger acid has weaker conjugate base

pH definition

pH = −log[H⁺] | pOH = −log[OH⁻] | pH + pOH = 14

Henderson-Hasselbalch equation

pH = pKa + log([A⁻]/[HA])

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Used to find pH of buffer solutions

Degree of dissociation (weak acid)

α = √(Ka/C)

C = initial concentration of weak acid

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Valid when α << 1

pH of weak acid

pH = ½(pKa − log C)

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Easier form of Henderson equation for pure weak acid

Ch 8Redox Reactions(8 formulas)

Oxidation number: free element

ON = 0 (e.g. Fe, Cl₂, S₈)

Oxidation number: monoatomic ion

ON = charge of ion (e.g. Na⁺ → +1, Cl⁻ → −1)

Oxidation number: oxygen

ON(O) = −2 usually; −1 in peroxides (H₂O₂); +2 in OF₂

Oxidation number: hydrogen

ON(H) = +1 usually; −1 in metal hydrides (NaH)

n-factor (acid-base)

n-factor = basicity of acid or acidity of base

n-factor (redox)

n-factor = change in oxidation number per formula unit

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In ionic equations: n-factor = total electrons transferred per formula unit

Equivalents (for calculations)

Equivalents = moles × n-factor | N = M × n-factor

Half-reaction method (acidic)

Add H₂O to balance O, then H⁺ to balance H, then e⁻ to balance charge

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